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Algebra / Chinese

Matrix Distributivity: Keep the Common Factor on the Right

均一教育平台 Junyi Academy · YouTube · 2:26

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The explanation, unpacked.

Reviewed learning material · Video analysis · English
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A complete2×2 worked example keeps the common factor C on the right, rewrites AC+BC as(A+BA+B)C and finishes the addition and multiplication to obtain[[1,9],[3,-8]]. It applies distributivity rather than proving the general theorem. Original notes state compatible dimensions and distinguish horizontal rows from vertical columns.

Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.

Chapters

0:00Reading the Problem and Analyzing Matrix Dimensions0:31Applying the Distributive Law of Matrix Multiplication0:49Calculating Matrix Addition A+BA+B1:13Problem Analysis and Application of Distributive Law1:28Detailed Calculation of Matrix Multiplication2:18Conclusion and Answer Verification

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

The problem asks for AC+BC. Both terms share C on the right, so keep its position and combine them as(A+BA+B)C.

Add entries in matching positions to obtain A+B=[[2,3],[1,−1]]A+B=[[2,3],[1,-1]], then multiply this sum by C on the right.

Each product entry pairs a row of the left matrix with a column of the right matrix. The top-left entry is four minus three, giving one; the top-right is minus six plus fifteen, giving nine.

The second row follows the same rule: two plus one gives three, and minus three minus five gives minus eight, producing[[1,9],[3,-8]].

This completes the numerical example. In general, A and B have size m×nm\times n and C has size n×pn\times p. That dimension statement is editorial, and the common right factor must remain on the right.

Knowledge cards

01

Matrices

Keep the common right factor and apply AC+BC=(A+BA+B)C in this2×2 example. In general A and B are m×nm\times n and C is n×pn\times p; the source does not prove the general theorem.

AC+BC=(A+B)CAC + BC = (A+B)C
02

2x2 Matrix Addition Example

To add two matrices of the same order, simply add the elements at corresponding positions. For example, in this problem, the element in the first row and first column of A+BA+B is calculated as 7+(−5)=27 + (-5) = 2, and the element in the first row and second column is -9 + 12=312 = 3.

[7−9−53]+[−5126−4]=[231−1]\begin{bmatrix} 7 & -9 \\ -5 & 3 \end{bmatrix} + \begin{bmatrix} -5 & 12 \\ 6 & -4 \end{bmatrix} = \begin{bmatrix} 2 & 3 \\ 1 & -1 \end{bmatrix}
03

Right Distributive Law of Matrix Multiplication

When AC, BC, and A+BA+B are all defined, AC + BC = (A+BA+B)C. This property allows us to simplify two matrix multiplications into one matrix addition and one matrix multiplication, which is particularly applicable when multiple terms share the same right-side matrix.

AC+BC=(A+B)CAC + BC = (A+B)C
04

Calculation Rules for 2x2 Matrix Multiplication

The element in the i-th row and j-th column of the resulting matrix equals the dot product of the i-th row vector of the left matrix and the j-th column vector of the right matrix. That is, multiply corresponding elements and sum them up. For example, when calculating the top-left element, you need to multiply the two numbers in the first row of the left matrix by the two numbers in the first column of the right matrix respectively, and then add the two products.

Detailed learning notes

Explore conditions, steps and evidence. Supplementary explanations are labeled separately from content shown in the video.

Symbols · 6

A

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays A=[7−9−53]A = \begin{bmatrix} 7 & -9 \\ -5 & 3 \end{bmatrix}

Symbol

A

Meaning

Given 2x2 matrix

Domain

2x2 real matrices

B

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays B=[−5126−4]B = \begin{bmatrix} -5 & 12 \\ 6 & -4 \end{bmatrix}

Symbol

B

Meaning

Given 2x2 matrix

Domain

2x2 real matrices

C

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays C=[2−3−15]C = \begin{bmatrix} 2 & -3 \\ -1 & 5 \end{bmatrix}

Symbol

C

Meaning

Given 2x2 matrix

Domain

2x2 real matrices

A

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays A=[[7,−9],[−5,3]]A = [[7, -9], [-5, 3]]

Symbol

A

Meaning

Given matrix A

Domain

2x2 matrix

B

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays B=[[−5,12],[6,−4]]B = [[-5, 12], [6, -4]]

Symbol

B

Meaning

Given matrix B

Domain

2x2 matrix

C

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays C=[[2,−3],[−1,5]]C = [[2, -3], [-1, 5]]

Symbol

C

Meaning

Given matrix C

Domain

2x2 matrix

Knowledge points · 4

Right Distributive Law of Matrix Multiplication

Clear evidence
Supplementary explanation
Evidence
  1. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

  2. Formula
    Observation

    The screen displays AC + BC = (A+BA+B)C

Formula
Explanation

When the dimensions of matrices A, B, and C are such that AC, BC, and A+BA+B are all defined, the right distributive law can be used to transform AC + BC into (A+BA+B)C, thereby simplifying the calculation.

Formula
AC+BC=(A+B)CAC + BC = (A+B)C
Conditions
  1. A and B have size m×nm\times n, C has size n×pn\times p; all three source matrices are2×2.

  2. The source demonstrates this numerical example and uses the general distributive law as a known rule, without proving it.

Right Distributive Law of Matrix Multiplication

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    The screen displays AC + BC = (A+BA+B)C

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Formula
Explanation

When AC, BC, and A+BA+B are all defined, the right distributive law of matrix multiplication can be used to transform AC + BC into (A+BA+B)C for calculation.

Formula
AC+BC=(A+B)CAC + BC = (A+B)C
Conditions
  1. A and B have size m×nm\times n, C has size n×pn\times p; all three source matrices are2×2.

  2. The source demonstrates this numerical example and uses the general distributive law as a known rule, without proving it.

Matrix Addition

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays the calculation process and result of A+BA+B as [[2, 3], [1, -1]]

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Method
Explanation

Add the corresponding elements of two matrices of the same order to obtain a new matrix.

Formula
Conditions
  1. The two matrices must have the same order

Matrix Multiplication

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    The screen displays the expanded calculation process of (A+BA+B)C

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Method
Explanation

Pair each horizontal row of the left factor with each vertical column of the right factor, multiply corresponding entries and sum to obtain the corresponding result entry.

Formula
Conditions
  1. The number of columns of the left factor equals the number of rows of the right factor; both factors here are2×2.

Derivations and proofs · 2

Calculating AC+BC using the Distributive Law

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    The screen step-by-step shows substituting the matrices and calculating A+BA+B

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Uncertainties
  1. Only the current0–73second analysis interval lacks the final product; the later source completes all calculations and the answer.

Proof
Steps
  1. Expression
    AC+BC=(A+B)CAC + BC = (A+B)C
    Explanation

    Apply the right distributive law of matrix multiplication

    Justification

    Distributive law of matrix multiplication

    Shown in the video
  2. Expression
    =([7−9−53]+[−5126−4])[2−3−15]= \left( \begin{bmatrix} 7 & -9 \\ -5 & 3 \end{bmatrix} + \begin{bmatrix} -5 & 12 \\ 6 & -4 \end{bmatrix} \right) \begin{bmatrix} 2 & -3 \\ -1 & 5 \end{bmatrix}
    Explanation

    Substitute the known matrices A, B, and C into the expression

    Justification

    Problem conditions

    Shown in the video
  3. Expression
    =[231−1][2−3−15]= \begin{bmatrix} 2 & 3 \\ 1 & -1 \end{bmatrix} \begin{bmatrix} 2 & -3 \\ -1 & 5 \end{bmatrix}
    Explanation

    Calculate the matrix addition inside the parentheses: 7+(−5)=27+(-5)=2, -9+12=312=3, -5+6=16=1, 3+(−4)=−13+(-4)=-1

    Justification

    Definition of matrix addition

    Shown in the video
Conclusion

The current0–73second interval reaches(A+BA+B)C; the later full source gives[[1,9],[3,-8]].

Derivation of Simplifying Matrix Operations Using the Distributive Law

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen step-by-step displays the complete derivation from AC+BC to the final result

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Proof
Steps
  1. Expression
    AC+BC=(A+B)CAC + BC = (A+B)C
    Explanation

    Apply the right distributive law of matrix multiplication to transform the original expression into a form of adding first and then multiplying.

    Justification

    Distributive law of matrix multiplication

    Shown in the video
  2. Expression
    A+B=[[7,−9],[−5,3]]+[[−5,12],[6,−4]]=[[2,3],[1,−1]]A+B = [[7, -9], [-5, 3]] + [[-5, 12], [6, -4]] = [[2, 3], [1, -1]]
    Explanation

    Calculate the sum of matrices A and B by adding corresponding elements.

    Justification

    Definition of matrix addition

    Shown in the video
  3. Expression
    (A+B)C=[[2,3],[1,−1]]∗[[2,−3],[−1,5]](A+B)C = [[2, 3], [1, -1]] * [[2, -3], [-1, 5]]
    Explanation

    Multiply the calculated result of A+BA+B with matrix C.

    Justification

    Substitution

    Shown in the video
  4. Expression
    (1,1):2∗2+3∗(−1)=4−3=1(1,1):2*2 + 3*(-1) = 4 - 3 = 1
    Explanation

    Calculate the top-left element of the resulting matrix.

    Justification

    Definition of matrix multiplication

    Supplementary explanation
  5. Expression
    (1,2):2∗(−3)+3∗5=−6+15=9(1,2):2*(-3) + 3*5 = -6 + 15 = 9
    Explanation

    Calculate the top-right element of the resulting matrix.

    Justification

    Definition of matrix multiplication

    Supplementary explanation
  6. Expression
    (2,1):1∗2+(−1)∗(−1)=2+1=3(2,1):1*2 + (-1)*(-1) = 2 + 1 = 3
    Explanation

    Calculate the bottom-left element of the resulting matrix.

    Justification

    Definition of matrix multiplication

    Supplementary explanation
  7. Expression
    (2,2):1∗(−3)+(−1)∗5=−3−5=−8(2,2):1*(-3) + (-1)*5 = -3 - 5 = -8
    Explanation

    Calculate the bottom-right element of the resulting matrix.

    Justification

    Definition of matrix multiplication

    Supplementary explanation
Conclusion

AC + BC = [[1, 9], [3, -8]]

Worked examples · 2

Matrix Calculation Example

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    The screen displays the complete problem and part of the solution process

Uncertainties
  1. Only the current0–73second analysis interval lacks the final product; the later source completes all calculations and the answer.

Problem

Given matrices A, B, and C, find the value of AC + BC.

Given
  1. A=[7−9−53]A = \begin{bmatrix} 7 & -9 \\ -5 & 3 \end{bmatrix}

  2. B=[−5126−4]B = \begin{bmatrix} -5 & 12 \\ 6 & -4 \end{bmatrix}

  3. C=[2−3−15]C = \begin{bmatrix} 2 & -3 \\ -1 & 5 \end{bmatrix}

Goal

Calculate AC + BC

Steps
  1. Expression
    AC+BC=(A+B)CAC + BC = (A+B)C
    Explanation

    Use the distributive law of matrix multiplication to factor out C

    Justification

    Right distributive law of matrix multiplication

    Shown in the video
  2. Expression
    A+B=[231−1]A+B = \begin{bmatrix} 2 & 3 \\ 1 & -1 \end{bmatrix}
    Explanation

    Add corresponding elements to calculate A+BA+B

    Justification

    Definition of matrix addition

    Shown in the video
Answer

The current0–73second interval completes only A+BA+B; the later full source obtains[[1,9],[3,-8]].

Verification

Editorial independent computation gives A+B=[[2,3],[1,−1]]A+B=[[2,3],[1,-1]] and AC+BC=[[1,9],[3,-8]], agreeing with the complete final source answer.

Example Application of the Distributive Law of Matrix Multiplication

Clear evidence
Supplementary explanation
Evidence
  1. Formula
    Observation

    The screen fully presents the problem conditions and solution process

  2. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Problem

Given matrices A=[[7,−9],[−5,3]]A=[[7,-9],[-5,3]], B=[[−5,12],[6,−4]]B=[[-5,12],[6,-4]], and C=[[2,−3],[−1,5]]C=[[2,-3],[-1,5]], find the value of AC+BC.

Given
  1. A=[[7,−9],[−5,3]]A=[[7,-9],[-5,3]]

  2. B=[[−5,12],[6,−4]]B=[[-5,12],[6,-4]]

  3. C=[[2,−3],[−1,5]]C=[[2,-3],[-1,5]]

Goal

Calculate AC+BC

Steps
  1. Expression
    AC+BC=(A+B)CAC + BC = (A+B)C
    Explanation

    Observe that AC, BC, and A+BA+B are all defined, so decide to use the distributive law to simplify the calculation.

    Justification

    Right distributive law of matrix multiplication

    Shown in the video
  2. Expression
    A+B=[[2,3],[1,−1]]A+B = [[2, 3], [1, -1]]
    Explanation

    First perform matrix addition by adding the corresponding elements of A and B.

    Justification

    Matrix addition

    Shown in the video
  3. Expression
    (A+B)C=[[1,9],[3,−8]](A+B)C = [[1, 9], [3, -8]]
    Explanation

    Perform matrix multiplication between the addition result and C, calculating the four positional elements one by one.

    Justification

    Matrix multiplication

    Shown in the video
Answer

[[1, 9], [3, -8]]

Verification

The final source matrix is[[1,9],[3,-8]]. Independently computing AC and BC and adding them gives the same answer.

Visual events · 2

Cursor Highlights Distributive Law Structure

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    A yellow cursor moves over and circles C and (A+BA+B) in AC+BC=(A+BA+B)C

Objects
  1. Yellow circular cursor

  2. Formula AC+BC=(A+BA+B)C

Changes
  1. Cursor moves and circles specific parts of the formula

Invariants
  1. Formula content remains unchanged

Interpretation

Visually emphasizes extracting the common right-multiplied matrix C, leaving A+BA+B.

Cursor Highlighting Guides Visual Focus

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    The yellow cursor moves among different numbers in the formula and highlights them according to the speaker's explanation

Objects
  1. Yellow circular cursor

  2. Numbers in the formula

Changes
  1. The cursor sequentially stays on the elements being calculated

Invariants
  1. The underlying formula structure remains unchanged

Interpretation

Dynamic highlighting helps learners track the correspondence and calculation progress of individual elements in complex matrix operations.

Concept relations · 3

Right Distributive Law of Matrix Multiplication → Matrix Calculation Example

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Application
Explanation

The right distributive law of matrix multiplication is applied to simplify this matrix calculation example.

Right Distributive Law of Matrix Multiplication → Matrix Addition

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen first writes AC+BC=(A+BA+B)C, then calculates A+BA+B

Application
Explanation

The application of the distributive law transforms the problem into one requiring matrix addition first.

Matrix Addition → Matrix Multiplication

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen substitutes the result of A+BA+B and multiplies it by C

Application
Explanation

The result of matrix addition serves as one of the inputs for matrix multiplication to continue the calculation.

Find an answer · 4

How is the distributive law of matrix multiplication used to simplify AC+BC?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays AC+BC=(A+BA+B)C

Knowledge points
  1. Right Distributive Law of Matrix Multiplication

How do you perform addition on 2x2 matrices?

Clear evidence
Shown in the video
Evidence
  1. Formula
    Observation

    The screen displays the matrix addition calculation process

Knowledge points
  1. Matrix Calculation Example

When can the distributive law of matrix multiplication be used to simplify the calculation of AC+BC?

Clear evidence
Shown in the video
Evidence
  1. Audio
    Observation

    The narration relates the current equations to distributivity, entrywise addition or row-by-column multiplication.

Knowledge points
  1. Right Distributive Law of Matrix Multiplication

When performing 2x2 matrix multiplication, how can one ensure that row and column elements correspond correctly without omission?

Clear evidence
Shown in the video
Evidence
  1. Animation
    Observation

    The cursor moves following the calculation steps

Knowledge points
  1. Matrix Multiplication
Coverage and review notes

Covered · Reading the problem and confirming matrix dimensions. Local transition note: The adjacent transition from reading the problem to the distributive law is included in the complete provided audio/video.

Covered · Explaining and applying the distributive law of matrix multiplication. Local transition note: The adjacent transition from this method to substituting values is included in the complete provided audio/video.

Covered · Substituting values and calculating A+BA+B

Covered · Introduces the problem and applies the distributive law to transform AC+BC into (A+BA+B)C, completing the matrix addition calculation.

Covered · Demonstrates the matrix multiplication process of (A+BA+B) and C in detail, calculating the four elements one by one.

Covered · Summarizes the final answer and concludes the lecture.

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  • Matrices ExplanationAt 0:31
    Why this connection?

    Keep the common right factor and apply AC+BC=(A+BA+B)C in this2×2 example. In general A and B are m×nm\times n and C is n×pn\times p; the source does not prove the general theorem.