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Calculus / English

A Complete Guide to Improper Integrals

inTuition · YouTube · 9:52

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Handle every improper feature of an integral and avoid canceling separately divergent pieces.

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Chapters

0:00Find all improper points4:30Split before taking limits7:30The pieces diverge

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The integral of 1/(x−1)1/(x-1)³ from 0 to infinity has both an infinite endpoint and an interior singularity at x=1x=1. Treating only the infinite endpoint misses an essential condition.

Split at x=1x=1 and use separate one-sided limits for the left and right pieces, as well as a limit at infinity. An ordinary improper integral converges only if every required piece converges finitely.

The antiderivative is −1/[2(x−1)2(x-1)²]. Approaching the singularity from the left makes the left integral tend to −infinity; the right integral tends to +infinity. They cannot be canceled to assign an ordinary integral value.

Knowledge cards

01

Find all improper points

The integral of 1/(x−1)1/(x-1)³ from 0 to infinity has both an infinite endpoint and an interior singularity at x=1x=1. Treating only the infinite endpoint misses an essential condition.

02

Split before taking limits

Split at x=1x=1 and use separate one-sided limits for the left and right pieces, as well as a limit at infinity. An ordinary improper integral converges only if every required piece converges finitely.

03

The pieces diverge

The antiderivative is −1/[2(x−1)2(x-1)²]. Approaching the singularity from the left makes the left integral tend to −infinity; the right integral tends to +infinity. They cannot be canceled to assign an ordinary integral value.

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  • Improper integrals ExplanationAt 0:00
    Why this connection?

    The integral of 1/(x−1)1/(x-1)³ from 0 to infinity has both an infinite endpoint and an interior singularity at x=1x=1. Treating only the infinite endpoint misses an essential condition. Split at x=1x=1 and use separate one-sided limits for the left and right pieces, as well as a limit at infinity. An ordinary improper integral converges only if every required piece converges finitely. The antiderivative is −1/[2(x−1)2(x-1)²]. Approaching the singularity from the left makes the left integral tend to −infinity; the right integral tends to +infinity. They cannot be canceled to assign an ordinary integral value.