Skip to content
Back to exploration
Calculus / English

Taylor Series and Maclaurin Series - Calculus 2

The Organic Chemistry Tutor · YouTube · 29:21

Open original
READ & KEEP

The explanation, unpacked.

Saves 0

Reviewed learning material · Video analysis · English
Read the full overview

Construct Taylor and Maclaurin series from derivative values, then create new series by differentiation and substitution.

Use the learning inspector for key ideas and moments, or open the reading tabs for the complete notes.

Chapters

3:00Expand around one13:30Odd powers of sine24:00Transform a known series

Learning script

Generated from the video's visuals and explanation; not verbatim speech.

For ln x around x=1x=1, derivative values give (x−1x-1)−(x−1x-1)²/2+(x−1x-1)³/3−⋯. Equality with the function holds for |x−1x-1|<1; endpoints require separate checking.

At zero, the even-power coefficients of sine vanish and the odd-power terms alternate: x−xx-x³/3!+x⁵/5!−⋯. This series converges to sine for every real x.

Termwise differentiation gives the cosine series; replacing x by x² then gives 1−x1-x⁴/2!+x⁸/4!−⋯ for cos(x²). These operations are justified within the power series’ convergence range.

Knowledge cards

01

Expand around one

For ln x around x=1x=1, derivative values give (x−1x-1)−(x−1x-1)²/2+(x−1x-1)³/3−⋯. Equality with the function holds for |x−1x-1|<1; endpoints require separate checking.

02

Odd powers of sine

At zero, the even-power coefficients of sine vanish and the odd-power terms alternate: x−xx-x³/3!+x⁵/5!−⋯. This series converges to sine for every real x.

03

Transform a known series

Termwise differentiation gives the cosine series; replacing x by x² then gives 1−x1-x⁴/2!+x⁸/4!−⋯ for cos(x²). These operations are justified within the power series’ convergence range.

Explore the knowledge in this video

Open video knowledge graph →

  • Taylor series ExplanationAt 3:00
    Why this connection?

    For ln x around x=1x=1, derivative values give (x−1x-1)−(x−1x-1)²/2+(x−1x-1)³/3−⋯. Equality with the function holds for |x−1x-1|<1; endpoints require separate checking. At zero, the even-power coefficients of sine vanish and the odd-power terms alternate: x−xx-x³/3!+x⁵/5!−⋯. This series converges to sine for every real x. Termwise differentiation gives the cosine series; replacing x by x² then gives 1−x1-x⁴/2!+x⁸/4!−⋯ for cos(x²). These operations are justified within the power series’ convergence range.